(8x^3-26x+22x-4)/(x-1)

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Solution for (8x^3-26x+22x-4)/(x-1) equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

(8*x^3-(26*x)+22*x-4)/(x-1) = 0

(8*x^3-26*x+22*x-4)/(x-1) = 0

(8*x^3-4*x-4)/(x-1) = 0

8*x^3-4*x-4 = 0

4*(2*x^3-x-1) = 0

2*x^3-x-1 = 0

{ 1, -1 }

1

x = 1

2*x^3-x-1 = 0

1

x-1

2*x^2+2*x+1

2*x^3-x-1

x-1

2*x^2-2*x^3

2*x^2-x-1

2*x-2*x^2

x-1

1-x

0

2*x^2+2*x+1 = 0

DELTA = 2^2-(1*2*4)

DELTA = -4

DELTA < 0

x in { 1} 

4*(x-1) = 0

4 = 0

x belongs to the empty set

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